x^2+60x+15=0

Solution for x^2+60x+15=0 equation:

x^2+60x+15=0

a = 1; b = 60; c = +15;
Δ = b2-4ac
Δ = 602-4·1·15
Δ = 3540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3540}=\sqrt{4*885}=\sqrt{4}*\sqrt{885}=2\sqrt{885}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-2\sqrt{885}}{2*1}=\frac{-60-2\sqrt{885}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+2\sqrt{885}}{2*1}=\frac{-60+2\sqrt{885}}{2}
$